2[2+3(y-1)]=2

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Solution for 2[2+3(y-1)]=2 equation:


Simplifying
2[2 + 3(y + -1)] = 2

Reorder the terms:
2[2 + 3(-1 + y)] = 2
2[2 + (-1 * 3 + y * 3)] = 2
2[2 + (-3 + 3y)] = 2

Combine like terms: 2 + -3 = -1
2[-1 + 3y] = 2
[-1 * 2 + 3y * 2] = 2
[-2 + 6y] = 2

Solving
-2 + 6y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 6y = 2 + 2

Combine like terms: -2 + 2 = 0
0 + 6y = 2 + 2
6y = 2 + 2

Combine like terms: 2 + 2 = 4
6y = 4

Divide each side by '6'.
y = 0.6666666667

Simplifying
y = 0.6666666667

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